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@@ -377,7 +377,7 @@ f(x) = F'(x) = 4x - 4x^3.
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\E(X) \amp = \int_0^1 x f(x)\ dx \\
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\amp = \int_0^1 x (4x - 4x^3)\ dx \\
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\amp = \int_0^1 4x^2 - 4x^4\ dx \\
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\amp = \frac{4x^2}{3} - \frac{4x^5}{5}\bigg|_0^1 \\
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\amp = \frac{4x^3}{3} - \frac{4x^5}{5}\bigg|_0^1 \\
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\amp = \left(\frac{4}{3} - \frac{4}{5}\right) - (0) \\
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\amp = \frac{8}{15} \approx 0.533.
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\end{align*}
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