The sample space, often denoted \(\Omega\text{,}\) is the set of all possible results of an experiment. A single result is called an outcome, while a collection of results is called an event.
An experiment consists of rolling a standard 6-sided die. The sample space is \(\Omega = \{1, 2, 3, 4, 5, 6\}\text{.}\) One possible event is \(A = \{2, 4, 6\}\text{,}\) i.e., the event that the result of the roll is even.
Let \(A\) be a set. The symbol \(\in\) means "is an element of", as in \(a \in A\text{.}\) Given another set \(B\text{,}\) we say \(A\) is a subset of \(B\text{,}\) written \(A\subset B\text{,}\) to mean that every element of the set \(A\) is also an element of the set \(B\text{.}\)
Find \(|A|\text{,}\)\(|B|\text{,}\)\(|C|\text{,}\)\(|A\cup B|\text{,}\)\(|A \cap B|\text{,}\)\(|B\cap C|\text{,}\)\(|A\cap C|\text{,}\) and \(|A\cup B\cup C|\text{.}\) Is it true that the size of the union of sets is equal to the sum of the sizes of the individual sets?
\(|A| = 10\text{,}\)\(|B| = 7\text{,}\)\(|C| = 7\text{,}\)\(|A \cup B| = 13\text{,}\)\(|A \cap B| = 4\text{,}\)\(|B\cap C| = 3\text{,}\)\(|A\cap C| = 2\text{,}\)\(|A\cup B\cup C| = 17\text{.}\) In particular, note that \(|A\cup B| = 13 \neq 10 + 7 = |A| + |B|\text{,}\) so it is not true in general that the size of the union of sets is the sum of the sizes of the individual sets.
Suppose we roll a 6-sided die two times. List the set of all possible results. [Note: the result (2, 4)---rolling a 2 and then a 4---is different from the result \((4, 2)\)---rolling a 4 and then a 2.]
Suppose we flip a coin two times. List the set of all possible results. What about flipping three times? Four times? If we flip the coin 10 times, how many possible results will there be?