Set Theory solutions
This commit is contained in:
+152
-36
@@ -10,8 +10,10 @@
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<definition xml:id="def-sample-space">
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<statement>
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<p>
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The <term>sample space</term>, often denoted <m>\Omega</m>, is the set of all possible results of an experiment.
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A single result is called an <term>outcome</term>, while a collection of results is called an <term>event</term>.
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The <term>sample space</term>, often denoted <m>\Omega</m>, is the set
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of all possible results of an experiment.
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A single result is called an <term>outcome</term>, while a collection of
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results is called an <term>event</term>.
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</p>
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</statement>
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</definition>
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@@ -21,11 +23,13 @@
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<p>
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An experiment consists of rolling a standard 6-sided die.
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The sample space is <m>\Omega = \{1, 2, 3, 4, 5, 6\}</m>.
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One possible event is <m>A = \{2, 4, 6\}</m>, i.e., the event that the result of the roll is even.
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One possible event is <m>A = \{2, 4, 6\}</m>, i.e., the event that the
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result of the roll is even.
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</p>
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<p>
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What would the sample space look like if we roll the die two times and recorded the results?
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What would the sample space look like if we roll the die two times and
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recorded the results?
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</p>
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</statement>
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@@ -39,7 +43,8 @@
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<mrow> \amp (5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6), </mrow>
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<mrow> \amp (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)\} </mrow>
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</md>
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Note that, for example, <m>(1, 2)</m> is a different outcome from <m>(2, 1)</m>.
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Note that, for example, <m>(1, 2)</m> is a different outcome from
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<m>(2, 1)</m>.
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</p>
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</answer>
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</example>
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@@ -49,25 +54,31 @@
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<p>
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Let <m>A</m> be a set.
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The symbol <m>\in</m> means "is an element of", as in <m>a \in A</m>.
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Given another set <m>B</m>, we say <m>A</m> is a <term>subset</term> of <m>B</m>, written <m>A\subset B</m>, to mean that every element of the set <m>A</m> is also an element of the set <m>B</m>.
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Given another set <m>B</m>, we say <m>A</m> is a <term>subset</term> of
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<m>B</m>, written <m>A\subset B</m>, to mean that every element of the
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set <m>A</m> is also an element of the set <m>B</m>.
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</p>
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</statement>
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</definition>
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<p>
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The subset symbol includes the possibility that <m>A</m> and <m>B</m> are equal sets, i.e., that they contain precisely the same elements.
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The subset symbol includes the possibility that <m>A</m> and <m>B</m> are
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equal sets, i.e., that they contain precisely the same elements.
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</p>
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<definition xml:id="def-set-operations">
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<statement>
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<p>
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Consider sets <m>A</m> and <m>B</m>, each contained inside <m>\Omega</m>.
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We can combine sets in a variety of ways: <dl>
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Consider sets <m>A</m> and <m>B</m>, each contained inside
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<m>\Omega</m>.
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We can combine sets in a variety of ways:
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<dl>
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<li>
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<title>Union</title>
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<p>
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The <term>union</term> of <m>A</m> and <m>B</m> is the set <m>A \cup B = \{x \mid x \in A \text{ or } x \in B\}</m>.
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The <term>union</term> of <m>A</m> and <m>B</m> is the set
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<m>A \cup B = \{x \mid x \in A \text{ or } x \in B\}</m>.
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</p>
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</li>
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@@ -75,7 +86,8 @@
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<title>Intersection</title>
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<p>
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The <term>intersection</term> of <m>A</m> and <m>B</m> is the set <m>A \cap B = \{x \mid x \in A \text{ and } x \in B\}</m>.
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The <term>intersection</term> of <m>A</m> and <m>B</m> is the set
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<m>A \cap B = \{x \mid x \in A \text{ and } x \in B\}</m>.
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</p>
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</li>
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@@ -83,7 +95,8 @@
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<title>Difference</title>
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<p>
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The <term>set difference</term> <m>A-B</m> is the set <m>A - B = \{x \mid x \in A \text{ and } x \notin B\}</m>.
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The <term>set difference</term> <m>A-B</m> is the set
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<m>A - B = \{x \mid x \in A \text{ and } x \notin B\}</m>.
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</p>
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</li>
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@@ -91,7 +104,8 @@
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<title>Complement</title>
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<p>
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The <term>complement</term> of <m>A</m> is the set <m>A^c = \{x \in \Omega \mid x \notin A\}</m>.
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The <term>complement</term> of <m>A</m> is the set
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<m>A^c = \{x \in \Omega \mid x \notin A\}</m>.
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</p>
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</li>
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@@ -99,7 +113,8 @@
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<title>Empty Set</title>
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<p>
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The <term>empty set</term>, usually written <m>\emptyset</m> or <m>\{\}</m>, is the set which contains no elements.
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The <term>empty set</term>, usually written <m>\emptyset</m> or
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<m>\{\}</m>, is the set which contains no elements.
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</p>
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</li>
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</dl>
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@@ -108,7 +123,8 @@
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</definition>
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<p>
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It's useful sometimes to draw pictures called <term>Venn diagrams</term> representing sets:
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It's useful sometimes to draw pictures called <term>Venn diagrams</term>
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representing sets:
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</p>
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<figure xml:id="fig-Venn-diagram">
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@@ -116,7 +132,8 @@
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<image width="50%">
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<description>
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<p>
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Venn diagram showing sets <m>A, B, C</m> with the region representing <m>(A\cup B\cup C) - (A \cap C)</m> shaded.
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Venn diagram showing sets <m>A, B, C</m> with the region representing
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<m>(A\cup B\cup C) - (A \cap C)</m> shaded.
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</p>
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</description>
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<latex-image>
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@@ -144,7 +161,8 @@
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<definition xml:id="def-disjoint">
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<statement>
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<p>
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Two sets <m>A</m> and <m>B</m> are <term>disjoint</term> if <m>A \cap B = \emptyset</m>.
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Two sets <m>A</m> and <m>B</m> are <term>disjoint</term> if
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<m>A \cap B = \emptyset</m>.
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</p>
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</statement>
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</definition>
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@@ -152,20 +170,22 @@
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<definition xml:id="def-cardinality">
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<statement>
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<p>
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Given a finite set <m>A</m>, the <term>cardinality</term> of <m>A</m>, written <m>|A|</m>, is the number of elements in <m>A</m>.
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Given a finite set <m>A</m>, the <term>cardinality</term> of <m>A</m>,
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written <m>|A|</m>, is the number of elements in <m>A</m>.
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</p>
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</statement>
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</definition>
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<exercises xml:id="exercises-Set-Theory">
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<exercise>
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<introduction>
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<p>
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Consider the sets <m>A = \{1, 2, 3, 4, 5, 6, 7, 8, 9, 10\}</m>, <m>B = \{2, 4, 9, 10, 12, 14, 19\}</m>, and <m>C = \{9, 10, 11, 14, 16, 17, 20\}</m>, which are all subsets of <m>\Omega = \{1, 2, 3, \dotsc, 20\}</m>.
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Consider the sets <m>A = \{1, 2, 3, 4, 5, 6, 7, 8, 9, 10\}</m>,
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<m>B = \{2, 4, 9, 10, 12, 14, 19\}</m>, and
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<m>C = \{9, 10, 11, 14, 16, 17, 20\}</m>, which are all subsets of
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<m>\Omega = \{1, 2, 3, \dotsc, 20\}</m>.
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</p>
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</introduction>
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<task>
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<statement>
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<p>
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@@ -178,24 +198,78 @@
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<m>\{1, 2, 3, 4, 5, 6, 7, 8\}</m>
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</p>
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</answer>
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</task>
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<solution>
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<p>
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The set <m>A - (B \cap C)</m> consists of elements in the set
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<m>A</m> which are not in the overlap of <m>B</m> and <m>C</m>.
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The overlap is <m>B \cap C = \{9, 10, 14\}</m>, and of these
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elements, <m>9</m> and <m>10</m> are in <m>A</m>.
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So <m>A - (B \cap C) = \{1, 2, 3, 4, 5, 6, 7, 8\}</m>.
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</p>
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</solution>
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</task>
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<task>
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<statement>
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<p>
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Find <m>|A|</m>, <m>|B|</m>, <m>|C|</m>, <m>|A\cup B|</m>, <m>|A \cap B|</m>, <m>|B\cap C|</m>, <m>|A\cap C|</m>, and <m>|A\cup B\cup C|</m>.
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Is it true that the size of the union of sets is equal to the sum of the sizes of the individual sets?
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Find <m>|A|</m>, <m>|B|</m>, <m>|C|</m>, <m>|A\cup B|</m>,
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<m>|A \cap B|</m>, <m>|B\cap C|</m>, <m>|A\cap C|</m>, and
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<m>|A\cup B\cup C|</m>.
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Is it true that the size of the union of sets is equal to the sum of
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the sizes of the individual sets?
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</p>
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</statement>
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<answer>
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<p>
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<m>|A| = 10</m>, <m>|B| = 7</m>, <m>|C| = 7</m>, <m>|A \cup B| = 13</m>, <m>|A \cap B| = 4</m>, <m>|B\cap C| = 3</m>, <m>|A\cap C| = 2</m>, <m>|A\cup B\cup C| = 17</m>. In particular, note that <m>|A\cup B| = 13 \neq 10 + 7 = |A| + |B|</m>, so it is not true in general that the size of the union of sets is the sum of the sizes of the individual sets.
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<m>|A| = 10</m>, <m>|B| = 7</m>, <m>|C| = 7</m>,
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<m>|A \cup B| = 13</m>, <m>|A \cap B| = 4</m>, <m>|B\cap C| = 3</m>,
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<m>|A\cap C| = 2</m>, <m>|A\cup B\cup C| = 17</m>.
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In particular, note that
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<m>|A\cup B| = 13 \neq 10 + 7 = |A| + |B|</m>, so it is not true in
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general that the size of the union of sets is the sum of the sizes
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of the individual sets.
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</p>
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</answer>
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</task>
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<solution>
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<p>
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<m>|X|</m> counts the number of elements in a finite set <m>X</m>.
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We can quickly count the elements in sets <m>A, B, C</m> to see that
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<m>|A| = 10</m>, <m>|B| = 7</m>, and <m>|C| = 7</m>.
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</p>
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<p>
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The union of two sets includes all elements from either set, so:
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<md>
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<mrow> A \cup B \amp = \{1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 12, 14, 19\} </mrow>
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<mrow> A \cup B \cup C \amp = \{1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 14, 16, 17, 19, 20\} </mrow>
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</md>
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Counting the elements, we see <m>|A \cup B| = 13</m> and
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<m>|A \cup B \cup C| = 17</m>.
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</p>
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<p>
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The intersection of two sets is the overlap, consisting of elements
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which show up in both sets simultaneously, so:
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<md>
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<mrow> A \cap B \amp = \{2, 4, 9, 10\} </mrow>
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<mrow> B \cap C \amp = \{9, 10, 14\} </mrow>
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<mrow> A \cap C \amp = \{9, 10\} </mrow>
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</md>
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Counting the elements, we see <m>|A\cap B| = 4</m>,
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<m>|B \cap C| = 3</m>, and <m>|A\cap C| = 2</m>.
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</p>
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<p>
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In particular, note that
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<m>|A\cup B| = 13 \neq 10 + 7 = |A| + |B|</m>, so it is not true in
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general that the size of the union of sets is the sum of the sizes
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of the individual sets.
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</p>
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</solution>
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</task>
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<task>
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<statement>
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@@ -206,19 +280,33 @@
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<answer>
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<p>
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<m>A^c = \{11, 12, 13, 14, 15, 16, 17, 18, 19, 20\}</m>, <m>(A\cup B)^c = \{11, 13, 15, 16, 17, 18, 20\}</m>.
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<m>A^c = \{11, 12, 13, 14, 15, 16, 17, 18, 19, 20\}</m>,
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<m>(A\cup B)^c = \{11, 13, 15, 16, 17, 18, 20\}</m>.
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</p>
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</answer>
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<solution>
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<p>
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<m>A^c</m> consists of elements of <m>\Omega</m> which are not in
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<m>A</m>, thus
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<m>A^c = \{11, 12, 13, 14, 15, 16, 17, 18, 19, 20\}</m>.
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Similarly, <m>(A\cup B)^c</m> consists of elements that are not in
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<m>A</m> nor in <m>B</m>.
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Therefore, <m>(A\cup B)^c = \{11, 13, 15, 16, 17, 18, 20\}</m>.
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</p>
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</solution>
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</task>
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</exercise>
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<exercise>
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<statement>
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<p>
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Suppose we have a 6-sided die that's weighted to roll a 6 half of the time.
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Suppose we have a 6-sided die that's weighted to roll a 6 half of the
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time.
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We roll the die two times.
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List the set of all possible results.
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[Note: the result (2, 4)---rolling a 2 and then a 4---is different from the result <m>(4, 2)</m>---rolling a 4 and then a 2.]
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[Note: the result (2, 4)---rolling a 2 and then a 4---is different
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from the result <m>(4, 2)</m>---rolling a 4 and then a 2.]
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</p>
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</statement>
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@@ -232,10 +320,25 @@
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<mrow> \amp (5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6), </mrow>
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<mrow> \amp (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)\} </mrow>
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</md>
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Note that <m>\Omega</m> simply lists outcomes with no reference to the probabilities.
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So the answer here is the same as in <xref ref="example-sample-space"/>.
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</p>
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</answer>
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<solution>
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<p>
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<md>
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<mrow> \Omega = \{\amp (1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), </mrow>
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<mrow> \amp (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6), </mrow>
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<mrow> \amp (3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6), </mrow>
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<mrow> \amp (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6), </mrow>
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<mrow> \amp (5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6), </mrow>
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<mrow> \amp (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)\} </mrow>
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</md>
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Note that <m>\Omega</m> simply lists outcomes with no reference to the
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probabilities.
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So the answer here is the same as in
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<xref ref="example-sample-space"/>.
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</p>
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</solution>
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</exercise>
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<exercise>
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@@ -243,7 +346,9 @@
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<p>
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Suppose we flip a coin two times.
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List the set of all possible results.
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What about flipping three times? Four times? If we flip the coin 10 times, how many possible results will there be?
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What about flipping three times?
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Four times?
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If we flip the coin 10 times, how many possible results will there be?
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</p>
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</statement>
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@@ -253,7 +358,11 @@
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</p>
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<p>
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For three flips: <m>\Omega = \{ HHH, HHT, HTH, THH, HTT, THT, TTH, TTT \}</m>.
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For three flips:
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<md>
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<mrow> \Omega = \{ \amp HHH, HHT, HTH, THH, </mrow>
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<mrow> \amp HTT, THT, TTH, TTT \}</mrow>
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</md>
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</p>
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<p>
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@@ -276,16 +385,23 @@
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<exercise>
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<statement>
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<p>
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If we roll a 6-sided die ten times, how many possible results will there be?
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If we roll a 6-sided die ten times, how many possible results will
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there be?
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</p>
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</statement>
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<answer>
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<p>
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Each additional roll will multiply the number of outcomes by 6.
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So, with 10 rolls, we'll have <m>|\Omega| = 6^{10}.</m>
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<m>|\Omega| = 6^{10}</m>.
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</p>
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</answer>
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<solution>
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<p>
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Each additional roll will multiply the number of outcomes by 6.
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So, with 10 rolls, we'll have <m>|\Omega| = 6^{10}</m>.
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</p>
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</solution>
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</exercise>
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</exercises>
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</section>
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Block a user