Figured out the list error
This commit is contained in:
+115
-55
@@ -62,9 +62,7 @@
|
||||
<statement>
|
||||
<p>
|
||||
Consider sets <m>A</m> and <m>B</m>, each contained inside <m>\Omega</m>.
|
||||
We can combine sets in a variety of ways:
|
||||
</p>
|
||||
<dl>
|
||||
We can combine sets in a variety of ways: <dl>
|
||||
<li>
|
||||
<title>Union</title>
|
||||
|
||||
@@ -105,6 +103,7 @@
|
||||
</p>
|
||||
</li>
|
||||
</dl>
|
||||
</p>
|
||||
</statement>
|
||||
</definition>
|
||||
|
||||
@@ -220,8 +219,6 @@
|
||||
<statement>
|
||||
<p>
|
||||
A <term>probability distribution</term> on a sample space <m>\Omega</m> assigns probabilities to every event, satisfying the following conditions:
|
||||
</p>
|
||||
|
||||
<ol>
|
||||
<li>
|
||||
<p>
|
||||
@@ -241,9 +238,74 @@
|
||||
</p>
|
||||
</li>
|
||||
</ol>
|
||||
</p>
|
||||
</statement>
|
||||
</definition>
|
||||
|
||||
<p>
|
||||
For small probability spaces (i.e., with finitely many outcomes in the sample space), we'll usually assign probabilities to each individual outcome, and perhaps list them in a table.
|
||||
Then, to find the probability of any event, simply add together the probabilities of each outcome in that event.
|
||||
</p>
|
||||
|
||||
<example>
|
||||
<statement>
|
||||
<p>
|
||||
An experiment consists of rolling a standard 6-sided die.
|
||||
The sample space is <m>\Omega = \{1, 2, 3, 4, 5, 6\}</m>.
|
||||
The probability distribution (assuming a fair die) is shown below.
|
||||
</p>
|
||||
|
||||
<table>
|
||||
<title>Distribution for a fair die</title>
|
||||
|
||||
<tabular halign="center">
|
||||
<row bottom="minor">
|
||||
<cell><m>x</m></cell>
|
||||
<cell><m>\Pr(x)</m></cell>
|
||||
</row>
|
||||
|
||||
<row>
|
||||
<cell>1</cell>
|
||||
<cell><m>1/6</m></cell>
|
||||
</row>
|
||||
|
||||
<row>
|
||||
<cell>2</cell>
|
||||
<cell><m>1/6</m></cell>
|
||||
</row>
|
||||
|
||||
<row>
|
||||
<cell>3</cell>
|
||||
<cell><m>1/6</m></cell>
|
||||
</row>
|
||||
|
||||
<row>
|
||||
<cell>4</cell>
|
||||
<cell><m>1/6</m></cell>
|
||||
</row>
|
||||
|
||||
<row>
|
||||
<cell>5</cell>
|
||||
<cell><m>1/6</m></cell>
|
||||
</row>
|
||||
|
||||
<row>
|
||||
<cell>6</cell>
|
||||
<cell><m>1/6</m></cell>
|
||||
</row>
|
||||
</tabular>
|
||||
</table>
|
||||
|
||||
<p>
|
||||
One possible event is <m>A = \{2, 4, 6\}</m>, i.e., the event that the result of the roll is even.
|
||||
The probability of <m>A</m> is:
|
||||
<md>
|
||||
<mrow> \Pr(A) = \Pr(2) + \Pr(4) + \Pr(6) = \frac{1}{6} + \frac{1}{6} + \frac{1}{6} = \frac{3}{6} = \frac{1}{2} </mrow>
|
||||
</md>
|
||||
</p>
|
||||
</statement>
|
||||
</example>
|
||||
|
||||
<exercises xml:id="exercises-Probability">
|
||||
<exercise>
|
||||
<statement>
|
||||
@@ -255,31 +317,55 @@
|
||||
<table>
|
||||
<title></title>
|
||||
|
||||
<tabular>
|
||||
<row>
|
||||
<cell halign="center"><m>x</m></cell>
|
||||
<cell halign="center">1</cell>
|
||||
<cell halign="center">2</cell>
|
||||
<cell halign="center">3</cell>
|
||||
<cell halign="center">4</cell>
|
||||
<cell halign="center">5</cell>
|
||||
<cell halign="center">6</cell>
|
||||
<cell halign="center">7</cell>
|
||||
<cell halign="center">8</cell>
|
||||
<cell halign="center">9</cell>
|
||||
<tabular halign="center">
|
||||
<row bottom="minor">
|
||||
<cell><m>x</m></cell>
|
||||
<cell><m>\Pr(x)</m></cell>
|
||||
</row>
|
||||
|
||||
<row>
|
||||
<cell halign="center"><m>\Pr(x)</m></cell>
|
||||
<cell halign="center">0.1</cell>
|
||||
<cell halign="center">0.05</cell>
|
||||
<cell halign="center">0.2</cell>
|
||||
<cell halign="center">0.15</cell>
|
||||
<cell halign="center">0.15</cell>
|
||||
<cell halign="center">0.1</cell>
|
||||
<cell halign="center">0.05</cell>
|
||||
<cell halign="center">0.1</cell>
|
||||
<cell halign="center">0.1</cell>
|
||||
<cell>1</cell>
|
||||
<cell>0.1</cell>
|
||||
</row>
|
||||
|
||||
<row>
|
||||
<cell>2</cell>
|
||||
<cell>0.05</cell>
|
||||
</row>
|
||||
|
||||
<row>
|
||||
<cell>3</cell>
|
||||
<cell>0.2</cell>
|
||||
</row>
|
||||
|
||||
<row>
|
||||
<cell>4</cell>
|
||||
<cell>0.15</cell>
|
||||
</row>
|
||||
|
||||
<row>
|
||||
<cell>5</cell>
|
||||
<cell>0.15</cell>
|
||||
</row>
|
||||
|
||||
<row>
|
||||
<cell>6</cell>
|
||||
<cell>0.1</cell>
|
||||
</row>
|
||||
|
||||
<row>
|
||||
<cell>7</cell>
|
||||
<cell>0.05</cell>
|
||||
</row>
|
||||
|
||||
<row>
|
||||
<cell>8</cell>
|
||||
<cell>0.1</cell>
|
||||
</row>
|
||||
|
||||
<row>
|
||||
<cell>9</cell>
|
||||
<cell>0.1</cell>
|
||||
</row>
|
||||
</tabular>
|
||||
</table>
|
||||
@@ -511,35 +597,9 @@
|
||||
<exercise>
|
||||
<statement>
|
||||
<p>
|
||||
Let <m>A = \{1, 2, 3\}</m> and <m>B = \{3, 4, 5\}</m>.
|
||||
Fill in the following probability distribution table so that <m>A, B</m> are independent.
|
||||
Let <m>A = \{1, 2, 3\}</m> and <m>B = \{3, 4, 5\}</m> be events in the sample space <m>\Omega = \{1, 2, 3, 4, 5, 6\}</m>.
|
||||
Create a probability distribution for <m>\Omega</m> so that <m>A, B</m> are independent.
|
||||
</p>
|
||||
|
||||
<table>
|
||||
<title></title>
|
||||
|
||||
<tabular>
|
||||
<row>
|
||||
<cell halign="center"><m>x</m></cell>
|
||||
<cell halign="center">1</cell>
|
||||
<cell halign="center">2</cell>
|
||||
<cell halign="center">3</cell>
|
||||
<cell halign="center">4</cell>
|
||||
<cell halign="center">5</cell>
|
||||
<cell halign="center">6</cell>
|
||||
</row>
|
||||
|
||||
<row>
|
||||
<cell halign="center"><m>\Pr(x)</m></cell>
|
||||
<cell halign="center"></cell>
|
||||
<cell halign="center"></cell>
|
||||
<cell halign="center"></cell>
|
||||
<cell halign="center"></cell>
|
||||
<cell halign="center"></cell>
|
||||
<cell halign="center"></cell>
|
||||
</row>
|
||||
</tabular>
|
||||
</table>
|
||||
</statement>
|
||||
</exercise>
|
||||
</exercises>
|
||||
|
||||
Reference in New Issue
Block a user