From b4b9f041acf3e906bc765722ff59d070aa847fbc Mon Sep 17 00:00:00 2001
From: andyeisenberg
Date: Sun, 1 Feb 2026 09:44:40 -0500
Subject: [PATCH] Split sections in Ch 4
---
source/ch-Confidence-Intervals.ptx | 181 +---------------------------
source/docinfo.ptx | 2 +
source/sec-CLT.ptx | 64 ++++++++++
source/sec-Confidence-Intervals.ptx | 113 +++++++++++++++++
source/sec-Likelihood.ptx | 60 +++++++++
5 files changed, 243 insertions(+), 177 deletions(-)
create mode 100644 source/sec-CLT.ptx
create mode 100644 source/sec-Confidence-Intervals.ptx
create mode 100644 source/sec-Likelihood.ptx
diff --git a/source/ch-Confidence-Intervals.ptx b/source/ch-Confidence-Intervals.ptx
index 009ea2c..5e437ca 100644
--- a/source/ch-Confidence-Intervals.ptx
+++ b/source/ch-Confidence-Intervals.ptx
@@ -9,182 +9,9 @@
-
- Central Limit Theorem
+
+
+
-
- Text of section.
-
-
-
-
-
-
- Suppose a coin has probability 0.4 of coming up heads, and we flip the coin 100 times.
- Let S be the number of heads.
- Estimate the probability that 34 \leq S \leq 44.
-
-
-
-
-
-
-
- Suppose a fair die is rolled 100 times, and let m be the average value of the rolls.
- Estimate the probability that 3.45 \leq m \leq 3.55.
-
-
-
-
-
-
-
- The heights of men in the US have a mean of 69 in and a variance of about 9 in^2, and the heights of women in the US have a mean of 63.5 in with a variance of 6.25 in^2.
-
-
-
-
-
-
-
- Suppose the heights of 30 men are sampled, and a sample mean m is taken.
- Find the expected value and variance of m.
-
-
-
-
-
-
-
-
- Estimate the probability that m \geq 69.5.
-
-
-
-
-
-
-
-
- What if the sampled group was women?
-
-
-
-
-
-
-
-
- Confidence Intervals
-
-
- Text of section.
-
-
-
-
-
-
- Suppose we flip a coin 100 times and count 60 heads.
- Let p be the (unknown) probability that the coin comes up heads on a flip.
- Give an approximate 95% confidence interval for the value of p.
-
-
-
-
-
-
-
- Suppose in a sample of 100 people, 12 are left-handed.
-
-
-
-
-
-
-
- Give a 95% confidence interval for the proportion p of left-handed people.
-
-
-
-
-
-
-
-
- Give a 90% confidence interval.
-
-
-
-
-
-
-
-
- The weights of five mice are measured and recorded below.
- Give a 95% confidence interval for the sample mean weight of mice.
- (Pretend 5 measurements is large enough for the CLT to apply.)
-
-
-
-
-
-
-
- | mouse i |
- 1 |
- 2 |
- 3 |
- 4 |
- 5 |
-
-
-
- | weight \widetilde{w}_i (g) |
- 26 |
- 32 |
- 33 |
- 20 |
- 29 |
-
-
-
-
-
-
-
-
-
- The heights of five plants are measured and recorded below.
- Give a 95% confidence interval around the sample mean for the heights of the plants.
- (Pretend 5 measurements is large enough for the CLT to apply.)
-
-
-
-
-
-
-
- | plant i |
- 1 |
- 2 |
- 3 |
- 4 |
- 5 |
-
-
-
- | height \widetilde{h}_i (in) |
- 15 |
- 14 |
- 18 |
- 21 |
- 17 |
-
-
-
-
-
-
-
+
\ No newline at end of file
diff --git a/source/docinfo.ptx b/source/docinfo.ptx
index cc63dd0..500a474 100644
--- a/source/docinfo.ptx
+++ b/source/docinfo.ptx
@@ -36,6 +36,8 @@
\DeclareMathOperator{\E}{E}
\DeclareMathOperator{\Var}{Var}
\DeclareMathOperator{\Cov}{Cov}
+
+ \newcommand{\est}{\widehat}
diff --git a/source/sec-CLT.ptx b/source/sec-CLT.ptx
new file mode 100644
index 0000000..fa42cb5
--- /dev/null
+++ b/source/sec-CLT.ptx
@@ -0,0 +1,64 @@
+
+ Central Limit Theorem
+
+
+ Text of section.
+
+
+
+
+
+
+ Suppose a coin has probability 0.4 of coming up heads, and we flip the coin 100 times.
+ Let S be the number of heads.
+ Estimate the probability that 34 \leq S \leq 44.
+
+
+
+
+
+
+
+ Suppose a fair die is rolled 100 times, and let m be the average value of the rolls.
+ Estimate the probability that 3.45 \leq m \leq 3.55.
+
+
+
+
+
+
+
+ The heights of men in the US have a mean of 69 in and a variance of about 9 in^2, and the heights of women in the US have a mean of 63.5 in with a variance of 6.25 in^2.
+
+
+
+
+
+
+
+ Suppose the heights of 30 men are sampled, and a sample mean m is taken.
+ Find the expected value and variance of m.
+
+
+
+
+
+
+
+
+ Estimate the probability that m \geq 69.5.
+
+
+
+
+
+
+
+
+ What if the sampled group was women?
+
+
+
+
+
+
\ No newline at end of file
diff --git a/source/sec-Confidence-Intervals.ptx b/source/sec-Confidence-Intervals.ptx
new file mode 100644
index 0000000..2e85b13
--- /dev/null
+++ b/source/sec-Confidence-Intervals.ptx
@@ -0,0 +1,113 @@
+
+ Confidence Intervals
+
+
+ Text of section.
+
+
+
+
+
+
+ Suppose we flip a coin 100 times and count 60 heads.
+ Let p be the (unknown) probability that the coin comes up heads on a flip.
+ Give an approximate 95% confidence interval for the value of p.
+
+
+
+
+
+
+
+ Suppose in a sample of 100 people, 12 are left-handed.
+
+
+
+
+
+
+
+ Give a 95% confidence interval for the proportion p of left-handed people.
+
+
+
+
+
+
+
+
+ Give a 90% confidence interval.
+
+
+
+
+
+
+
+
+ The weights of five mice are measured and recorded below.
+ Give a 95% confidence interval for the sample mean weight of mice.
+ (Pretend 5 measurements is large enough for the CLT to apply.)
+
+
+
+
+
+
+
+ | mouse i |
+ 1 |
+ 2 |
+ 3 |
+ 4 |
+ 5 |
+
+
+
+ | weight \widetilde{w}_i (g) |
+ 26 |
+ 32 |
+ 33 |
+ 20 |
+ 29 |
+
+
+
+
+
+
+
+
+
+ The heights of five plants are measured and recorded below.
+ Give a 95% confidence interval around the sample mean for the heights of the plants.
+ (Pretend 5 measurements is large enough for the CLT to apply.)
+
+
+
+
+
+
+
+ | plant i |
+ 1 |
+ 2 |
+ 3 |
+ 4 |
+ 5 |
+
+
+
+ | height \widetilde{h}_i (in) |
+ 15 |
+ 14 |
+ 18 |
+ 21 |
+ 17 |
+
+
+
+
+
+
+
\ No newline at end of file
diff --git a/source/sec-Likelihood.ptx b/source/sec-Likelihood.ptx
new file mode 100644
index 0000000..f8591fc
--- /dev/null
+++ b/source/sec-Likelihood.ptx
@@ -0,0 +1,60 @@
+
+ Likelihood
+
+
+ So far, we've been concerned with probability theory.
+ Starting with a probability distribution and some parameter values, we've tried to answer questions like: What's the probability of seeing certain experimental results? Statistics is concerned with going in the other direction: Upon seeing the experimental results, can we determine the type of underlying probability distribution? Can we determine its parameters?
+
+
+
+
+
+ An estimator is a value of a parameter computed from a sample of data.
+
+
+
+
+
+
+ Suppose we find a coin on the street and don't know whether or not it's fair.
+ We want to know the probability p of the coin coming up heads.
+ We might, for example, flip the coin n times and count the number k of heads.
+ Then, we'll estimate p = \frac{k}{n}.
+ We'll refer to this as a common sense estimator.
+ (Other distributions and parameter types will have different notions of "common sense".)
+
+
+
+
+ An estimator is, itself, a random variable: it produces a numerical value based on the results of an experiment.
+ We'll use notation like \est{p} for a random variable which is an estimator for a parameter p.
+ (Similarly, \est{\lambda} would denote an estimator for a parameter called \lambda.)
+
+
+
+
+
+ An estimator \est{p} is called unbiased if \E(\est{p}) = p.
+
+
+
+
+
+
+
+ Suppose we have a coin with parameter p, which we'll flip n times and count the number k of heads.
+ We use the unbiased estimator \est{p} = \frac{k}{n}.
+ In this case, notice that k \sim \Bin(n, p), so we know \E(k) = np, although we don't know the value of p.
+ (We probably do know the value of n; after all, we're flipping the coin!) Now:
+
+ \E(\est{p}) = \E\left(\frac{k}{n}\right) = \frac{1}{n} \cdot \E(k) = \frac{1}{n} \cdot np = p.
+
+ It's worth pausing for a moment to be appropriately impressed with ourselves.
+ We still don't know the true value of p.
+ But we managed to show that our common sense method of estimating p gives, on average, the correct value.
+
+
+
+
+
+
\ No newline at end of file